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m^2-23m-24=0
a = 1; b = -23; c = -24;
Δ = b2-4ac
Δ = -232-4·1·(-24)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-25}{2*1}=\frac{-2}{2} =-1 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+25}{2*1}=\frac{48}{2} =24 $
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